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Question:
integrate x^3dx/1 x^4
Answer:

The question is like ∫x3 dx/1+x4

let x4 = y

then 4x3 dx = dy

         =>x3 dx = dy/4

Now  1/4∫ dy/(1+y)

        1/4 * log(1+y) + c where c is a constant

put the value of y we get

       1/4 *log(1+x4)

 

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